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anonymous

  • 5 years ago

A solid generated when region in the first quadrant is enclosed by curves y=2x^2 and y^2=4x is revolved around the x-axis. What is the volume? A. Pi/5 B. 2Pi/5 C. 8Pi/5 D. 6Pi/5 I got d, but I think I did something wrong. Can anyone else check my answer?

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  1. anonymous
    • 5 years ago
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    you've got two bounding equations. y=sqrt(4x) is your upper, and y=2x^2 is your lower. Find your area between them and multiply by 2pi

  2. anonymous
    • 5 years ago
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    I got 2/3 as the area between the two functions. If I multiplied it by 2Pi, I would not get any of the answers.

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