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- anonymous

solve the equation: the square root of x^2-3x+25=x+2

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- anonymous

solve the equation: the square root of x^2-3x+25=x+2

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- anonymous

set it =0 and use the quadratic formula.

- anonymous

\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}

- anonymous

\[\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}\]

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- anonymous

\[\sqrt{x ^{2}-3x+25}=x+2\]

- anonymous

wow what are you doing? That doesn't look right at all.

- anonymous

thats what the problem is , that s what i have to solve

- anonymous

Do you know what the quadratic formula is?

- anonymous

yeah but you dont use the quadratic formula for this problem

- anonymous

you got to square both sides but after that i have no idea what to do

- anonymous

Why can't you use the quadratic formula?

- anonymous

because this is solving radical equations

- anonymous

But this time you have another value of x aside from x^2

- anonymous

\[(\sqrt{x ^{2}-3x+25})^{2}=(x+2)^{2}\]

- anonymous

that problem is that you took a square root out of nowhere.

- anonymous

This is the first step in solving it , but then i dont know what to do, this is how i have it in my notes and how it has it in the book

- anonymous

a square cancels the square root on the left side

- anonymous

But if you take the square root of one side you have to take the square root of the other side. So that squared thing is pointless.

- anonymous

idk that s how the professor told us to do it

- anonymous

Ok do that square root thing but do it to BOTH SIDES

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