anonymous
  • anonymous
solve the equation: the square root of x^2-3x+25=x+2
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
set it =0 and use the quadratic formula.
anonymous
  • anonymous
\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}
anonymous
  • anonymous
\[\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}\]

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anonymous
  • anonymous
\[\sqrt{x ^{2}-3x+25}=x+2\]
anonymous
  • anonymous
wow what are you doing? That doesn't look right at all.
anonymous
  • anonymous
thats what the problem is , that s what i have to solve
anonymous
  • anonymous
Do you know what the quadratic formula is?
anonymous
  • anonymous
yeah but you dont use the quadratic formula for this problem
anonymous
  • anonymous
you got to square both sides but after that i have no idea what to do
anonymous
  • anonymous
Why can't you use the quadratic formula?
anonymous
  • anonymous
because this is solving radical equations
anonymous
  • anonymous
But this time you have another value of x aside from x^2
anonymous
  • anonymous
\[(\sqrt{x ^{2}-3x+25})^{2}=(x+2)^{2}\]
anonymous
  • anonymous
that problem is that you took a square root out of nowhere.
anonymous
  • anonymous
This is the first step in solving it , but then i dont know what to do, this is how i have it in my notes and how it has it in the book
anonymous
  • anonymous
a square cancels the square root on the left side
anonymous
  • anonymous
But if you take the square root of one side you have to take the square root of the other side. So that squared thing is pointless.
anonymous
  • anonymous
idk that s how the professor told us to do it
anonymous
  • anonymous
Ok do that square root thing but do it to BOTH SIDES

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