anonymous 5 years ago solve the equation: the square root of x^2-3x+25=x+2

1. anonymous

set it =0 and use the quadratic formula.

2. anonymous

\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}

3. anonymous

$\left\{\left\{x\to 2-i \sqrt{19}\right\},\left\{x\to 2+i \sqrt{19}\right\}\right\}$

4. anonymous

$\sqrt{x ^{2}-3x+25}=x+2$

5. anonymous

wow what are you doing? That doesn't look right at all.

6. anonymous

thats what the problem is , that s what i have to solve

7. anonymous

Do you know what the quadratic formula is?

8. anonymous

yeah but you dont use the quadratic formula for this problem

9. anonymous

you got to square both sides but after that i have no idea what to do

10. anonymous

Why can't you use the quadratic formula?

11. anonymous

because this is solving radical equations

12. anonymous

But this time you have another value of x aside from x^2

13. anonymous

$(\sqrt{x ^{2}-3x+25})^{2}=(x+2)^{2}$

14. anonymous

that problem is that you took a square root out of nowhere.

15. anonymous

This is the first step in solving it , but then i dont know what to do, this is how i have it in my notes and how it has it in the book

16. anonymous

a square cancels the square root on the left side

17. anonymous

But if you take the square root of one side you have to take the square root of the other side. So that squared thing is pointless.

18. anonymous

idk that s how the professor told us to do it

19. anonymous

Ok do that square root thing but do it to BOTH SIDES