derivative of Sec^2(3x) anyone? totally lost

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derivative of Sec^2(3x) anyone? totally lost

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\sec^2(3x) dx = { 6\sin(3x) \over (\cos(3x)^3)} \]
Remember the Chain Rule? Think of the problem as y = (sec3x)^2. Then dy/dx will be 2sec3x times d/dx(sec3x). Now all you need to do is differentiate sec3x. Hint: think of sec3w as 1/cos3x and use the quotient rule.
Thank you, that really helped clear the air!

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