## anonymous 5 years ago 8to the 6th pwr divided by 8 to the second pwr u keep the 8 but do you multiply,divide,subtract,or add the exponents?

1. anonymous

${8^6 \over 8^2} = {8*8*8*8*8*8 \over 8*8} = 8^{6-2} = 8^4$

2. anonymous

${a^x \over a^y} = a^{x-y}$$(a^x)(a^y) = a^{x+y}$$(a^x)^y = a^{xy}$$\sqrt[y]{a^x} = (a^{x})^{1 \over y} = a^{ x \over y }$

3. anonymous

does that help ?

4. anonymous

choices are a.8 to the 8th pwr b.8 to the 12th pwr c.8 to the 4th power d. 8 to the 3rd power