anonymous
  • anonymous
chemist dean dalton is given a clump of metal and is told that it is sodium. He finds that the metal weighs 145.5g. he places it into a nonreactice liquid in a square prism whose base measures 10cm on each edge. If the metal is indeed sodium, how high should the liquid level rise? The density of sodium is .97g/cm3 (answer and work please)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
toxicsugar22
  • toxicsugar22
hi math mind
anonymous
  • anonymous
haha hello sugar (:
toxicsugar22
  • toxicsugar22
can u help me after u help her

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
sure. I'll be right there
anonymous
  • anonymous
can I have help....?
anonymous
  • anonymous
sorry, i though you had left
anonymous
  • anonymous
yeah me too haha
anonymous
  • anonymous
answer please
anonymous
  • anonymous
yup, working on it
anonymous
  • anonymous
thanks
anonymous
  • anonymous
\[Density = {(mass) \over (volume)}\]\[Vsquare = (width)*(length)*(height)\]where: s = side/edge The initial volume of the square prism is: 10^3 = 10*10*10 = 1000 cm^3 to find the final volume (volume after the metal is added) we can use the density formula:\[(0.97) = {145.5 \over x}\](0.97)x = 145.5\[x = {145.5 \over 0.97} = 150 cm^3\] Therefore, if (volume) = (width)*(length)*(height) and if you add something the height would increase by x so, (10+x)\[150 cm^3 = 10*10*(10+x)\]150 = 100(10+x) 150 = 1000 + 100x 100x = 150-1000 x = 850/100 x = 8.5 cm rise

Looking for something else?

Not the answer you are looking for? Search for more explanations.