toxicsugar22
  • toxicsugar22
Andy drives 300 miles to Lake Tahoe at 70 miles per hour and returns home at 50 mph. What is his average speed for the round trip. (It is not 6o miles per hour.) Write expressions for the time it takes for each leg of the trip if Andy drives a distance d, at speed r base 1 and returns at speed r base 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Let the distance (of one way) be D the time taken to travel at 70 mph = D/70 the time taken to travel at 50 mph = D/50 total time taken = D/70 + D/50 \[{D \over 70} + {D \over 50} = {50D + 70D \over (70)(50)} = {120D \over 3500} = {12D \over 350}\]Total distance covered = D + D = 2D So, avg speed = \[{2D \over { 120D / (70*50)}} = {3500*2 \over 120} = 58.33 mph\]
anonymous
  • anonymous
did you understand my process ?
toxicsugar22
  • toxicsugar22
yes

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anonymous
  • anonymous
There's another way to approach this problem which is by calculating the time spent in each trip and divide by the total distance traveled 300/70=x 300/50=y 600/(x+y) = 58.33
toxicsugar22
  • toxicsugar22
ok so what is the ime trip to Taoe
toxicsugar22
  • toxicsugar22
time
anonymous
  • anonymous
the time trip TO taoe would be 300/70 = 4.29 hours
anonymous
  • anonymous
so did yu understand everthing ?
toxicsugar22
  • toxicsugar22
ok and the time from trip home
anonymous
  • anonymous
just like the way there: 300/50 = ?
toxicsugar22
  • toxicsugar22
ok i got it thanks

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