## anonymous 5 years ago Surface Area of the attached figure?

1. anonymous

2. anonymous

see the attached figure where green line length=$8\sqrt{2}$ so every lateral side length=16.49 (using pythagoras theorem); area of each side triangle $b(\sqrt{4a ^{2}-b ^{2}})/4$where a is the length of each equal side and b is the length of other side. here a=16.49, b=16 so we get tr. area=115.36 cm^2 for 4 such triangle....area 461.42 cm^2. and the base area 16^2=256. total area=717.42 sq cm.

3. anonymous

you can take help from the link http://www.ajdesigner.com/phptriangle/isosceles_triangle_area_k.php

4. anonymous

thanks!