some please work this problem completely step by step show ur work so i can follow along divide & simplify z^2-49 divided by 2z-14 ------- --------- z^2-8z+16 z^2-2z-63

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some please work this problem completely step by step show ur work so i can follow along divide & simplify z^2-49 divided by 2z-14 ------- --------- z^2-8z+16 z^2-2z-63

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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To divide fractions, you always have to invert (flip) the second fraction and multiply
\[\frac{z^2-49}{z^2-8z+16} * \frac{z^2-2z-63}{2z-14}\]
Next factor each part.

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Other answers:

\[\frac{(z-7)(z+7)}{(z-4)(z-4)} * \frac {(z-9)(z+7)}{2(z-7)}\]
sorry I'm so slow typing those equations
Then see what cancels (anything in the top with anything in the denominator)
so the z-7 will cancel. Nothing else will cancel
Everything that is still there is your answer....\[\frac{(z-9)(z+7)^2}{2(z-4)^2}\]
Does that make sense?
yes

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