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anonymous

  • 5 years ago

some please work this problem completely step by step show ur work so i can follow along divide & simplify z^2-49 divided by 2z-14 ------- --------- z^2-8z+16 z^2-2z-63

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  1. anonymous
    • 5 years ago
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    To divide fractions, you always have to invert (flip) the second fraction and multiply

  2. anonymous
    • 5 years ago
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    \[\frac{z^2-49}{z^2-8z+16} * \frac{z^2-2z-63}{2z-14}\]

  3. anonymous
    • 5 years ago
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    Next factor each part.

  4. anonymous
    • 5 years ago
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    \[\frac{(z-7)(z+7)}{(z-4)(z-4)} * \frac {(z-9)(z+7)}{2(z-7)}\]

  5. anonymous
    • 5 years ago
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    sorry I'm so slow typing those equations

  6. anonymous
    • 5 years ago
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    Then see what cancels (anything in the top with anything in the denominator)

  7. anonymous
    • 5 years ago
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    so the z-7 will cancel. Nothing else will cancel

  8. anonymous
    • 5 years ago
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    Everything that is still there is your answer....\[\frac{(z-9)(z+7)^2}{2(z-4)^2}\]

  9. anonymous
    • 5 years ago
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    Does that make sense?

  10. anonymous
    • 5 years ago
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    yes

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