solve: |x=6|-4=2

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solve: |x=6|-4=2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|x+6|-4=2
abs(x+6)=2+4=6 abs(x+6)=6 x+6=6 and x+6=-6 x=0 x=-12
example: abs(x)=6 what two values for x will give you distance 6 do you know?

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Other answers:

x+6 = 0 --> x=-6 -x-6 = 0 ---> x=-6
how far is -6 away from 0? how far is 6 away from 0?
they are both six units from 0
abs(x)=6 has two solutions x=6 and x=-6 just like we found 2 solutions above but these problems could get trickier along the way and sometimes it will fail to have two solutions so you should begin checking to get in the practice of doing so
so let's check the above one: we got x=0 and x=-12 lets see if x=0 works plug it into the original equation abs(0+6)-4=2 abs(6)-4=2 6-4=2 2=2 so we got the samething on both sides so x=0 checks out how about x=-12 abs(-12+6)-4=2 abs(-6)-4=2 6-4=2 2=2 so x=-12 checks out
any questions?
OK! That makes perfect sense once you broke it down for me!! Thank you both so very much :)
u r welcome
Really it's simply a matter of: \[|x+6| - 4 = 2 \implies |x+6| =6 \]\[\implies x + 6 = 6 \text{ and } x+ 6 = -6\] \[\implies x = 12 \text{ and } x = 0\] are solutions.
no polpak i already won
lol
lol. I have another one similar to that, think you could help? \[3x-1\le 7\]
and he meant x=-12 not 12
Yes, whoops.
Certainly, though this one doesn't involve absolute values.
add the 1 to both sides
what do you get after you do that?
\[3x \le8\]
and when you divide both sides by 3?
omg gj
3/3=1 so 3x/3=x so we have x<=8/3
good...got the same answer!!! Thanks.

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