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anonymous
 5 years ago
find the second derivative of x^2  y^2= 1
anonymous
 5 years ago
find the second derivative of x^2  y^2= 1

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.02x2yy'=0 solve for y' 2yy'=2x y'=2x/[2y]=x/y so y''=[(x)'(y)(x)(y)']/y^2 y''=[1yxy']/y^2 y''=[yxy']/y^2 but y'=x/y y''=[yx(x/y)]/y^2 y''=[yx^2/y]/y^2 lets get rid of the double fraction y''=[y^2x^2]/y^3 after multiply both top and bottom by y y''=[x^2y^2]/y^3 but omg x^2y^2=1 so y''=1/y^3 and done

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you so much! :)
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