## anonymous 5 years ago how do you solve a quadratic equation using the quadratic formula. Can someone explain this and show me an example so i get it...

1. anonymous

$ax^2 + bx +c = 0 \implies x=\frac{-(b) \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}$

2. myininaya

did you look at that scan i made for you?

3. anonymous

Just plug them in

4. anonymous

yes...I could not hardly read it.. sorry

5. myininaya

ok nvm then

6. anonymous

2x^2 + 10x + 3 = 0 a = 2 b = 10 c =3 D = sqrt(b^2-4ac) = sqrt (100-24) = sqrt(76) x = -b +- sqrt (D) ------------------ 2a

7. anonymous

So basically if you get something of the form you have on the right you plug it in to the formula on the left and you find the x values that make the right hand equation true.

8. anonymous

Err.. I have a hard time with right/left. So reverse what I said ;)

9. anonymous

Thank you..lol

10. myininaya

i hate right and left i use postive and negative when i talk

11. myininaya

i say lets go in the positive direction hoping people think i mean is it right?

12. anonymous

I appreciate all the help

13. myininaya

or left?

14. anonymous

ok

15. myininaya

i think its right

16. myininaya

polpak can i challenge you?

17. myininaya

lol

18. anonymous

with?