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anonymous

  • 5 years ago

how do you solve a quadratic equation using the quadratic formula. Can someone explain this and show me an example so i get it...

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  1. anonymous
    • 5 years ago
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    \[ax^2 + bx +c = 0 \implies x=\frac{-(b) \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}\]

  2. myininaya
    • 5 years ago
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    did you look at that scan i made for you?

  3. anonymous
    • 5 years ago
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    Just plug them in

  4. anonymous
    • 5 years ago
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    yes...I could not hardly read it.. sorry

  5. myininaya
    • 5 years ago
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    ok nvm then

  6. anonymous
    • 5 years ago
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    2x^2 + 10x + 3 = 0 a = 2 b = 10 c =3 D = sqrt(b^2-4ac) = sqrt (100-24) = sqrt(76) x = -b +- sqrt (D) ------------------ 2a

  7. anonymous
    • 5 years ago
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    So basically if you get something of the form you have on the right you plug it in to the formula on the left and you find the x values that make the right hand equation true.

  8. anonymous
    • 5 years ago
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    Err.. I have a hard time with right/left. So reverse what I said ;)

  9. anonymous
    • 5 years ago
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    Thank you..lol

  10. myininaya
    • 5 years ago
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    i hate right and left i use postive and negative when i talk

  11. myininaya
    • 5 years ago
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    i say lets go in the positive direction hoping people think i mean is it right?

  12. anonymous
    • 5 years ago
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    I appreciate all the help

  13. myininaya
    • 5 years ago
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    or left?

  14. anonymous
    • 5 years ago
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    ok

  15. myininaya
    • 5 years ago
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    i think its right

  16. myininaya
    • 5 years ago
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    polpak can i challenge you?

  17. myininaya
    • 5 years ago
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    lol

  18. anonymous
    • 5 years ago
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    with?

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spraguer (Moderator)
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