anonymous
  • anonymous
how do you solve a quadratic equation using the quadratic formula. Can someone explain this and show me an example so i get it...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[ax^2 + bx +c = 0 \implies x=\frac{-(b) \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}\]
myininaya
  • myininaya
did you look at that scan i made for you?
anonymous
  • anonymous
Just plug them in

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anonymous
  • anonymous
yes...I could not hardly read it.. sorry
myininaya
  • myininaya
ok nvm then
anonymous
  • anonymous
2x^2 + 10x + 3 = 0 a = 2 b = 10 c =3 D = sqrt(b^2-4ac) = sqrt (100-24) = sqrt(76) x = -b +- sqrt (D) ------------------ 2a
anonymous
  • anonymous
So basically if you get something of the form you have on the right you plug it in to the formula on the left and you find the x values that make the right hand equation true.
anonymous
  • anonymous
Err.. I have a hard time with right/left. So reverse what I said ;)
anonymous
  • anonymous
Thank you..lol
myininaya
  • myininaya
i hate right and left i use postive and negative when i talk
myininaya
  • myininaya
i say lets go in the positive direction hoping people think i mean is it right?
anonymous
  • anonymous
I appreciate all the help
myininaya
  • myininaya
or left?
anonymous
  • anonymous
ok
myininaya
  • myininaya
i think its right
myininaya
  • myininaya
polpak can i challenge you?
myininaya
  • myininaya
lol
anonymous
  • anonymous
with?

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