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or i mean what is the smaller possible value for n?

smallest*

Looks like the Chinese remainder theorem.

yay! :)

lol very good
yes i used euclidean's algorithm
which is mixed up with that Chinese stuff

i really like this problem

yeah I did something similar a few weeks ago to implement by hand RSA encryption

omg polpak i love the RSA

i want to be an expert at number theory

pretty cool. You can work for nsa ;)

I also looked at the secure hash algorithm 1 which is really just discrete math but still fun :)

all algorithms are just descrete math stuff ;p

yes thats true

what education level are you if you don't mind me asking?

About to transfer to 4 year university.

just finished the local CC.

what?!
no way

how are you super smart?

I'm old. Some smarts come with age. I also study a lot (comes with being old)

i think you are really cool :)

Well thanks. I'm 33 and started college a few years ago when my son was born.

are you going to be a math person? i mean you really already are, but do something with math?

math instructor?
engineer?
...

you can do it
you have the knowledge already for math

or some differential equations

I've done 1 class in diff eq's and 1 class in linear algebra thus far

are you american?

americans are lazy. you can't be american because you did that self study stuff

lol, yes I'm american. and yes, I'm lazy. most smart people are ;)

lol

I study cause it makes things easier

it's a lot more work to not know how to do the homework and struggle through it for hours and hours

yes i agree

i do have a another challenge question for you if you are willing to accept?

oh sure, though if it takes as long as euclid's algorithm I may have to hold off a while ;)

\[\int\limits_{}^{} e^{\sqrt{3x+9}} dx\]

evaluate the above is the question

or the problem

let me know if you want a hint k?

sorry, had a crisis..

its cool

looks like just u-sub then by parts..

not nearly as bad as some of the triple integrals I had last year in calc 3.

those things took pages =(

Whoops, should be 2u/3 I think actually

wait i think you can teach me something one sec

then integration by parts blah blah

some mistakes there

the only mistake i see is du=3/[2(3x+9)] dx but i really didn't use this simplification

It should be \[\frac{2}{3}\int ue^udu\]

oh darn it lol

I don't square nothin

I think you misunderstand what I did

me too

but that squaring does work also

my way is easier ;p

Then go back to the integral and sub that for dx, and the exponent of e just becomes u also.

oh i see lol

your awesome

you're ;p

ok, I'm off to watch a movie

ok =)

Mod[11, 3] = 2, Mod[11, 5] = 1