myininaya
  • myininaya
Polpak's Challenge Question Round 1 Let n be a positive integer. If we divide n by 3, the remainder is 2 If we divide n by 5, the remainder is 1 what is n?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
myininaya
  • myininaya
or i mean what is the smaller possible value for n?
myininaya
  • myininaya
smallest*
anonymous
  • anonymous
Looks like the Chinese remainder theorem.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

myininaya
  • myininaya
yay! :)
myininaya
  • myininaya
lol very good yes i used euclidean's algorithm which is mixed up with that Chinese stuff
myininaya
  • myininaya
i really like this problem
anonymous
  • anonymous
yeah I did something similar a few weeks ago to implement by hand RSA encryption
myininaya
  • myininaya
omg polpak i love the RSA
myininaya
  • myininaya
i want to be an expert at number theory
anonymous
  • anonymous
pretty cool. You can work for nsa ;)
myininaya
  • myininaya
my instructor may me look at the RSA because I said I was interested in number theory and i was kindof aftraid because i thought i was going to have to know some computer stuff, but all it really was was number theory i looked at the DSA which is fun too but not as fun as the RSA
myininaya
  • myininaya
I also looked at the secure hash algorithm 1 which is really just discrete math but still fun :)
myininaya
  • myininaya
i'm one of those people who get's the joke: There are 10 kinds of people in this world; those who know binary and those who don't
anonymous
  • anonymous
all algorithms are just descrete math stuff ;p
myininaya
  • myininaya
yes thats true
myininaya
  • myininaya
what education level are you if you don't mind me asking?
anonymous
  • anonymous
About to transfer to 4 year university.
anonymous
  • anonymous
just finished the local CC.
myininaya
  • myininaya
what?! no way
myininaya
  • myininaya
how are you super smart?
anonymous
  • anonymous
I'm old. Some smarts come with age. I also study a lot (comes with being old)
myininaya
  • myininaya
i think you are really cool :)
anonymous
  • anonymous
Well thanks. I'm 33 and started college a few years ago when my son was born.
myininaya
  • myininaya
are you going to be a math person? i mean you really already are, but do something with math?
myininaya
  • myininaya
math instructor? engineer? ...
anonymous
  • anonymous
Shooting for a masters in computer science, though I'm thinking I'll probably do math too. Maybe two masters! =)
myininaya
  • myininaya
you can do it you have the knowledge already for math
myininaya
  • myininaya
you probably know how to solve differential equations already i think you done one here before dont really remember
myininaya
  • myininaya
or some differential equations
anonymous
  • anonymous
I've done 1 class in diff eq's and 1 class in linear algebra thus far
myininaya
  • myininaya
are you american?
myininaya
  • myininaya
americans are lazy. you can't be american because you did that self study stuff
anonymous
  • anonymous
lol, yes I'm american. and yes, I'm lazy. most smart people are ;)
myininaya
  • myininaya
lol
anonymous
  • anonymous
I study cause it makes things easier
anonymous
  • anonymous
it's a lot more work to not know how to do the homework and struggle through it for hours and hours
myininaya
  • myininaya
yes i agree
myininaya
  • myininaya
i do have a another challenge question for you if you are willing to accept?
anonymous
  • anonymous
oh sure, though if it takes as long as euclid's algorithm I may have to hold off a while ;)
myininaya
  • myininaya
\[\int\limits_{}^{} e^{\sqrt{3x+9}} dx\]
myininaya
  • myininaya
evaluate the above is the question
myininaya
  • myininaya
or the problem
myininaya
  • myininaya
let me know if you want a hint k?
anonymous
  • anonymous
sorry, had a crisis..
myininaya
  • myininaya
its cool
anonymous
  • anonymous
looks like just u-sub then by parts..
anonymous
  • anonymous
\[u = \sqrt{3x + 9} \implies du = \frac{3}{u}dx \implies dx = \frac{u}{3}du\] \[\implies \int e^{\sqrt{3x+9}} dx = \frac{1}{3}\int ue^udu\] Then go with by-parts.
anonymous
  • anonymous
not nearly as bad as some of the triple integrals I had last year in calc 3.
anonymous
  • anonymous
those things took pages =(
anonymous
  • anonymous
Whoops, should be 2u/3 I think actually
myininaya
  • myininaya
wait i think you can teach me something one sec
myininaya
  • myininaya
1 Attachment
myininaya
  • myininaya
then integration by parts blah blah
anonymous
  • anonymous
some mistakes there
myininaya
  • myininaya
the only mistake i see is du=3/[2(3x+9)] dx but i really didn't use this simplification
anonymous
  • anonymous
It should be \[\frac{2}{3}\int ue^udu\]
anonymous
  • anonymous
What you have on the right side, second line is correct. but recall that sqrt(3x + 9) is u, so you just have u in the denominator
myininaya
  • myininaya
oh darn it lol
myininaya
  • myininaya
you way is much more easier instead of multiply by 1 you just freaking squared both sides of u=sqrt(3x+9) and got u^2=3x+9 so 2 du=3dx so dx=2du/3 you are freaking brillant lol not really i just didn't think of that i mean you are smart though
anonymous
  • anonymous
I don't square nothin
anonymous
  • anonymous
I think you misunderstand what I did
myininaya
  • myininaya
me too
myininaya
  • myininaya
but that squaring does work also
anonymous
  • anonymous
my way is easier ;p
anonymous
  • anonymous
Ok, Let \(u = \sqrt{3x + 9}\) \[\implies du = (\frac{1}{2\sqrt{3x+9}} * 3 )dx\] \[ = \frac{3}{2u}dx\] \[\implies dx = \frac{2u}{3}du\]
anonymous
  • anonymous
Then go back to the integral and sub that for dx, and the exponent of e just becomes u also.
myininaya
  • myininaya
oh i see lol
myininaya
  • myininaya
your awesome
anonymous
  • anonymous
you're ;p
anonymous
  • anonymous
ok, I'm off to watch a movie
myininaya
  • myininaya
k later peace i will see if i can come up with more challenging problems next time these sucked obviously
anonymous
  • anonymous
ok =)
anonymous
  • anonymous
Mod[11, 3] = 2, Mod[11, 5] = 1

Looking for something else?

Not the answer you are looking for? Search for more explanations.