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myininaya
 5 years ago
Polpak's Challenge Question
Round 1
Let n be a positive integer.
If we divide n by 3, the remainder is 2
If we divide n by 5, the remainder is 1
what is n?
myininaya
 5 years ago
Polpak's Challenge Question Round 1 Let n be a positive integer. If we divide n by 3, the remainder is 2 If we divide n by 5, the remainder is 1 what is n?

This Question is Closed

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1or i mean what is the smaller possible value for n?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Looks like the Chinese remainder theorem.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1lol very good yes i used euclidean's algorithm which is mixed up with that Chinese stuff

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i really like this problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah I did something similar a few weeks ago to implement by hand RSA encryption

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1omg polpak i love the RSA

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i want to be an expert at number theory

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0pretty cool. You can work for nsa ;)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1my instructor may me look at the RSA because I said I was interested in number theory and i was kindof aftraid because i thought i was going to have to know some computer stuff, but all it really was was number theory i looked at the DSA which is fun too but not as fun as the RSA

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1I also looked at the secure hash algorithm 1 which is really just discrete math but still fun :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i'm one of those people who get's the joke: There are 10 kinds of people in this world; those who know binary and those who don't

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all algorithms are just descrete math stuff ;p

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1what education level are you if you don't mind me asking?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0About to transfer to 4 year university.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just finished the local CC.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1how are you super smart?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm old. Some smarts come with age. I also study a lot (comes with being old)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i think you are really cool :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well thanks. I'm 33 and started college a few years ago when my son was born.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1are you going to be a math person? i mean you really already are, but do something with math?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1math instructor? engineer? ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Shooting for a masters in computer science, though I'm thinking I'll probably do math too. Maybe two masters! =)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you can do it you have the knowledge already for math

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you probably know how to solve differential equations already i think you done one here before dont really remember

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1or some differential equations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've done 1 class in diff eq's and 1 class in linear algebra thus far

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1americans are lazy. you can't be american because you did that self study stuff

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, yes I'm american. and yes, I'm lazy. most smart people are ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I study cause it makes things easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's a lot more work to not know how to do the homework and struggle through it for hours and hours

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i do have a another challenge question for you if you are willing to accept?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh sure, though if it takes as long as euclid's algorithm I may have to hold off a while ;)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{} e^{\sqrt{3x+9}} dx\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1evaluate the above is the question

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1let me know if you want a hint k?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, had a crisis..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0looks like just usub then by parts..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[u = \sqrt{3x + 9} \implies du = \frac{3}{u}dx \implies dx = \frac{u}{3}du\] \[\implies \int e^{\sqrt{3x+9}} dx = \frac{1}{3}\int ue^udu\] Then go with byparts.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not nearly as bad as some of the triple integrals I had last year in calc 3.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0those things took pages =(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Whoops, should be 2u/3 I think actually

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1wait i think you can teach me something one sec

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1then integration by parts blah blah

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1the only mistake i see is du=3/[2(3x+9)] dx but i really didn't use this simplification

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It should be \[\frac{2}{3}\int ue^udu\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What you have on the right side, second line is correct. but recall that sqrt(3x + 9) is u, so you just have u in the denominator

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you way is much more easier instead of multiply by 1 you just freaking squared both sides of u=sqrt(3x+9) and got u^2=3x+9 so 2 du=3dx so dx=2du/3 you are freaking brillant lol not really i just didn't think of that i mean you are smart though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't square nothin

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you misunderstand what I did

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1but that squaring does work also

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, Let \(u = \sqrt{3x + 9}\) \[\implies du = (\frac{1}{2\sqrt{3x+9}} * 3 )dx\] \[ = \frac{3}{2u}dx\] \[\implies dx = \frac{2u}{3}du\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then go back to the integral and sub that for dx, and the exponent of e just becomes u also.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, I'm off to watch a movie

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1k later peace i will see if i can come up with more challenging problems next time these sucked obviously

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Mod[11, 3] = 2, Mod[11, 5] = 1
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