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anonymous
 5 years ago
If z1  z2 = k, then find the radius of curvature of the locus arg(z1/z2) = θ
anonymous
 5 years ago
If z1  z2 = k, then find the radius of curvature of the locus arg(z1/z2) = θ

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so what does locus z1/z2 mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on the argand plane the locus corresponding to amplitude (z1/z2) = θ

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the radius of curvature is the circle that matches k, i recall that much

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at any given point along a curve in R3, it can be defined by the rate of curve withi respect to distance traveled along it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer in the book says (ksecθ) / 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah thats right but it has to be a quantity..the answers given..i dont get nething else

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the radius is te radius of the circle that matches the curvature produced; how to get it i cant recall

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0something about the tangent vector and the normal vector and hopw they interact

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0theres one more im posting...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0GUYS IAM NOT GETING IT PLZ HELP ME

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0an = k (ds/dt)^2 <N> but that doesnt seem to help does it lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur not getting what??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0PLZ SOLVE THIS QUESTION ONCE

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0acceleration has a 'tangent' and a 'normal component to it; the normal component is modified by k... but the details elude me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why would we need these physical quantities to solve an argand diagram..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0salman bhai post ur questions on the left side

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol...dunno, just recollecting what i read the other night about curvature and the radius of curvature

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0DO U KNOW URDU?????????????

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0my books all the way out inthe car so...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just hindi bhaijan..lil bit urdu

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im quasi proficient in english :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hahaha..im more proficient in english than hindi..written that is...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0salman bhai wts ur question??
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