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anonymous
 5 years ago
If z being a complex number lies on the unit circle and the sum of z with its reciprocal is 1, then find z^235
anonymous
 5 years ago
If z being a complex number lies on the unit circle and the sum of z with its reciprocal is 1, then find z^235

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0theres no answer given bt frm what i know it comes out to be a simple answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0z^2 +1  = 1; z^2 +1 = z; z^2 2 +1 = 0 Z

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but z isnt 1, its a complex number...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0z is the 3rd root of 1. because z^2Z+1=0; z^3=1 z^235=z=1+isqrt(3) /2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0z^2+1 = 1 z^2 = 0 z=0 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Z^3=1 (z+1)(z^2z+1)=0 Z^2z+1=0;

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so that means the the complex part is either up or down

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think dipankars right, did u apply the demoivres theorem??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no need to apply it....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dip is usually right ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have given the steps....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0z is the complex roots of 1.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so but then howdu get z^235??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u must realize amistre m doing wht u often do;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0z^235=z^234*z=(z^3*78)^z=1*z=z

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no not that...like wht u were doin with the tangent plane question...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with all the three ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its good to be smart :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0him i think u have understood the process...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so, when I find z=0, the complex parts have to be pure imaginaries then right? like "i"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0z + 1/z =1 let z=cosθ + isinθ 1/z = cosθ  isinθ z + 1/z = 2cosθ = 1 cosθ = 1/2 hence z = 1/2 + √3/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0z^235 = i^235...235/4 = 58 and 3 remaining i, 1, 1 z^235 = i?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no man look above z = 1/2 + i√3/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol...stab in the dark then :) i see what you did

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now du wanna know the other one as well?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i do, but at this late hour it aint gonna stick to well ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hahaha...wts d time there??
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