• anonymous
Find the volume of a solid generated by revolving the graphs of the functions y=6-2x-x^2 and y=x+6 about the line y=2 Intersections points are x=-3 and x=0 I think the radius of the solid should be 6-2x-x^2-(x+6)-2 which is -2-3x-x^2 then I have Vol = pi*Integral from -3 to 0 of (-2-3x-x^2)^2dx I integrate and get pi *[4x65/5+3/2x^4+13x^3/3+6x^2+4x ] evalulated between -3 and 0. I end up with 147.9pi which seems way too big.Can you find my mistake? Thank you so much!!!
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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