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anonymous
 5 years ago
Help please, Divide
(x³x+8) / (x2)
anonymous
 5 years ago
Help please, Divide (x³x+8) / (x2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x^3x+8=x^32x^2+2x^24x+3x6+14 =x^2(x2)+2x(x2)+3(x2)+14=(x^2+2x+3)(x2)+14 (x^3x+6)/(x2) =x^2+2x+3+[14/(x2)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im trying to writ this down on paper but... you lost me @ the second step

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see i have rewrite the expression so that i can take (x2) common.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see you have to divide with x2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have introduced 2x^2 to make with x^3 as x^2(x2). and i have add 2x^2 to nullify it...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have written x as 4x+3x. and 8 as 6 +14.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0have you now understood.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x^2 +2x +3  x2  x^3 x +8 x^3 +2x^2  2x^2 x +8 2x^2 +4x  3x +8 3x +6  14 < remainder

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the way it was written just threw me off, but i see how its done now thank you :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did yu get x^2 +2x +3 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nvm.. yu put the answer on the top. cool

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0see i had x^3x+8=x^2(x2)+2x(x2)+3(x2)+14=(x^2+2x+3)(x2)+14 so taking (x2 common from the first three terms i have (x^2+2x +3)(x2)
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