y=(m^2)x+(1/m) is the tangent to the parabola y^2 = 16x for what value of m?

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y=(m^2)x+(1/m) is the tangent to the parabola y^2 = 16x for what value of m?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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sub first in the second, expand out, you gert quadratic in x , find discriminant and set to zero
putting the equation of tangent in the eqn. of parabola we get (m^2x+1/m)^2=16x m^4x^2(2m-16)x+1/m^2=0. as it is a tangent so discriminant is 0. (2m-16)^2-4m^2=0 gives you m=4.
please check it.....

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the way you type is very annoying
should put brackets around stuff
all right. thanx you guys, that helped.
elecengineer .....i did it to make him understand the problem.....

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