anonymous
  • anonymous
y=(m^2)x+(1/m) is the tangent to the parabola y^2 = 16x for what value of m?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
sub first in the second, expand out, you gert quadratic in x , find discriminant and set to zero
anonymous
  • anonymous
putting the equation of tangent in the eqn. of parabola we get (m^2x+1/m)^2=16x m^4x^2(2m-16)x+1/m^2=0. as it is a tangent so discriminant is 0. (2m-16)^2-4m^2=0 gives you m=4.
anonymous
  • anonymous
please check it.....

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anonymous
  • anonymous
the way you type is very annoying
anonymous
  • anonymous
should put brackets around stuff
anonymous
  • anonymous
all right. thanx you guys, that helped.
anonymous
  • anonymous
elecengineer .....i did it to make him understand the problem.....

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