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think u mean by differentiaion

ok help me out please

F(x) + c

so the first is \[\frac{1}{2}\tan^{-1} (\frac{2x}{1-2x})\]

dont think its possbile
they must only differ by a constant

[S] [tan^-1 (2x/1-2X)]/2 = [S] tan^-1(1/x) right?

prob try some sum of angle formulas, possibly, but I dnt think it will make a difference

huh, maybe diff of angles formula

tan^-1(1/x) = u
-1/x^2
--------- dx = du perhaps
1 + 1/x^2

tan(u) = 1/x is what i was thinking lol; lost track mid type

the difference is an angle of \[\pi/2\]

eash man my bad ey guess you are a geenie

what, \[\frac{1}{2}\tan^{-1} (\frac{2x}{1-x^2}) \neq \tan^{-1} (\frac{1}{x})\]