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anonymous
 5 years ago
the sum of the series 20c0  20c1 + 20c2  20c3+........+20c10 is
anonymous
 5 years ago
the sum of the series 20c0  20c1 + 20c2  20c3+........+20c10 is

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.020(c0c1+c2c3 + ... + c10); what are the coeefs?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think it should use binomial form (1x)^20 or somewhat like it...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no no no hold on.. its a combinatorics problem. the 'c' here means that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use (1x)^20+(1+x)^20 you will get the ans...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0deeprony have u understood the p problem??????

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.020!/20!  20!/19! + 20!/18!2! .... like that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"(1x)^20+(1+x)^20" what is x here?? yea i understood that quetion=)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes mistre thats correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i stil gotta do these the brute force way ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0isint there a formula??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(1x)^20=20c020c1x+.......... now 20cn=20c20n. and thus 20c20=20c0. and so on put x=1. 20c020c1+.....=0 2(20c020c1.......+20c10)20c10=0 hence ans is (20c10)/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you explain what you did hre.. 20c020c1+.....=0 2(20c020c1.......+20c10)20c10=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i put just x=1 in the 1st expansion of (1x)^20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea ok wat did u do thn??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is the way of doing.....using a binomial series....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i had (1x)^20=20c020c1x+20c2x^2.... put x=1 0=20c020c1+20c2......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use 20c20=20c0,20c19=20c1,.......20c11=20c9.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got that olryt... i didnt understnd what u did xt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you get the term 20c0,20c1,....20c9 twice but 20c10 only one...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahh i c... got it now...=))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thus i write .. 0=2(20c020c1+20c2........+20c10)20c10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okkkkkkkkkkkkkkkkkk?????????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0these are some tricks to do it...............
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