the value of 2^(1/4).4^(1/8).8^(1/16).16(1/32)........................ is?

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the value of 2^(1/4).4^(1/8).8^(1/16).16(1/32)........................ is?

Mathematics
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2^(1/4+2/8+3/16+.....)
find the sum of AGP series....1/4+2/8+3/16+4/32
2^(13/16)

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Other answers:

this is not an AP, the 1st n 2nd term are the same isnt it?
yes it is AGP....
1/2^2 +(1+1)/2^3+(1+2)/2^4+(1+3)/2^5
AGP is airthmatic geomatric series
got it?????
tn=n/2^(n+1)
from tn you have to find Sn. here the series is small so you can add but otherwise you have to use series method.........
whats the series method??
check the page http://www.ilovemaths.com/3sequence.asp
this is an infinite series i guess we gotta use Sn= a/1-r need to break the question itno that form
no this form will not be applicable........
tn=n/2^(n+1) \[t _{n+1}=(n+1)/2^{n+2}=n/2^{n+2}+1/2^{n+2}\] \[t _{n+1}=t _{n}/2+1/2^{n+2}\] t2=t1/2+1/2^3 t3=t2/2+1/2^4 . . . --------------------- adding Sn-t1=Sn/2 +(1/2^3+1/2^4+.........) Sn/2=t1+(1/2^3+1/2^4....)
Sn/2=1/4+(1/2^3)(1/(1-1/2)) =1/4+1/4 Sn=1
hence 2^1=2
Got it?????
i think u have understood

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