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anonymous
 5 years ago
the value of 2^(1/4).4^(1/8).8^(1/16).16(1/32)........................ is?
anonymous
 5 years ago
the value of 2^(1/4).4^(1/8).8^(1/16).16(1/32)........................ is?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02^(1/4+2/8+3/16+.....)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0find the sum of AGP series....1/4+2/8+3/16+4/32

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is not an AP, the 1st n 2nd term are the same isnt it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/2^2 +(1+1)/2^3+(1+2)/2^4+(1+3)/2^5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0AGP is airthmatic geomatric series

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from tn you have to find Sn. here the series is small so you can add but otherwise you have to use series method.........

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats the series method??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0check the page http://www.ilovemaths.com/3sequence.asp

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is an infinite series i guess we gotta use Sn= a/1r need to break the question itno that form

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no this form will not be applicable........

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tn=n/2^(n+1) \[t _{n+1}=(n+1)/2^{n+2}=n/2^{n+2}+1/2^{n+2}\] \[t _{n+1}=t _{n}/2+1/2^{n+2}\] t2=t1/2+1/2^3 t3=t2/2+1/2^4 . . .  adding Snt1=Sn/2 +(1/2^3+1/2^4+.........) Sn/2=t1+(1/2^3+1/2^4....)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sn/2=1/4+(1/2^3)(1/(11/2)) =1/4+1/4 Sn=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think u have understood
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