A circle is defined by the following equation: x^(2)+y^(2)-8x+14y+47=0 What are the coordinates of its center?

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A circle is defined by the following equation: x^(2)+y^(2)-8x+14y+47=0 What are the coordinates of its center?

Mathematics
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(4,-7) :P
How did you get that so fast?
magic :p

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Okay magician, a circle is defined by the following equation: 3x^(2)+3y^(2)+30x+30y+150=0 What is its radius?
now the radius takes a little longer lol
x^2 +Y^2 +10X + 10Y + 50 =0 X^2 +10X+25 +Y^2 + 10Y + 25 + 50 =0 (X+5)^2 +(Y+5)^2 +50 =0
wait
should be (x+5)^2 +(y+5)^2 =0, WHICH IS NOT A CIRCLE
So then is 0 not the answer?
how can u have a circle of zero radius :P
a small one :)
idk, i have this as a qustion. it doesn't make sence.
teacher made a mistake
It's a computer program though.
well, its not a circle , a sum of sqaures cannot be zero ( in the real numbers anyway )
well, its not a circle , a sum of sqaures cannot be zero ( in the real numbers anyway )
the answer is definately not zero
would you say it is 10?
no I would say its not a circle

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