anonymous
  • anonymous
Help plz, Set up an equation to solve the following problem, and then solve it. On a sales trip, Irwin drove 330 miles averaging a certain speed. The return trip was at an average speed that is 11mph faster. Total time for the round trip was 11 hours. Find Irwin’s average speed on each part of the trip.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
well, its not hard , what dont we know , what we do we need to find , assign them to variables
radar
  • radar
Use distance equal rate times time.
anonymous
  • anonymous
let x equal the "certain speed"

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More answers

anonymous
  • anonymous
so assume 330 miles for one way , that means in total he drove 660miles
anonymous
  • anonymous
we know the total time was 11 but time = distance / speed time for first section = 330 / x times for second section = 330/ ( x+11) so ( 330/x) + [330 / (x+11) = 11
anonymous
  • anonymous
\[\frac{330}{x} + \frac{330}{x+11} =11\]
anonymous
  • anonymous
solve for x
anonymous
  • anonymous
i c. Thanks
anonymous
  • anonymous
it has two solutions x=-6, x=55 but because we are dealling with real world ( and yes, it says "speed", not velocity ) so a negative value is not allowed
anonymous
  • anonymous
so x=55 means for first half average was 55mph, and for second half average was 66mph ( ie 55 +11 )
radar
  • radar
Actually the average speed for the entire trip was 660/11 or 60 mi. So wouldn't that made the avg speed for the first part 54.5 mph and the second part 65.5?
anonymous
  • anonymous
dnt think so
radar
  • radar
The avg of 54.5 + 65.5 is 120/2=60
anonymous
  • anonymous
firstly where did u magically get 54.5 and 65.5 from
radar
  • radar
x + (x+11) 660 ---------- = ----- = 60 2 11
radar
  • radar
Nothing magic about it.
anonymous
  • anonymous
yes.... and.....?
anonymous
  • anonymous
yes there is , there are alot of different ways to get two numbers to sum to 120 , why did you pick those two numbers? , theres no calculations to suggest why you chose thoise two
anonymous
  • anonymous
ohh I think i see what you are doing now
anonymous
  • anonymous
bit of a dangerous way to think
radar
  • radar
x= first avg speed (certain speed) x+11 is the second avg speed (return trip Their sum divided by 2 equals the total avg speed 660/11 is also the total avg speed. Take it from there
radar
  • radar
Just sayin your way seems correct just wondering why they dont come out the same. Did you round off or take a root of or whatever/
anonymous
  • anonymous
no, the reason why they dont come out correct is because your way of thinking is wrong :P
radar
  • radar
Well they came out close.lol gotta run
anonymous
  • anonymous
:\, the average of a sum is not the sum of the avergaes
radar
  • radar
Gotcha, I see the error of my logic.

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