## anonymous 5 years ago If, the point (2,-1) is on the terminal side of angle 0, find the values of sin0,cos0,tan0

draw the picture and connect with the origin. you will see a right triangle, so all you need is the length of the hypotenuse. we get that by pythagoras:$\sqrt{2^2+(-1)^2}=\sqrt{5}$ the coordinates are (2,-1) $\cos(\theta)=\frac{2}{\sqrt{5}}$ $\sin(\theta)=\frac{-1}{\sqrt{5}}$ $tan(\theta)=\frac{-1}{2}$