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Depends on what you are doing, if you are expanding the log you could write it as: log(2) + log(x)
I was trying to do exactly the same. I was not sure if I could do that
then you need to take the ln of both sides.
Is there something else I can do now?
specially with the term ln(2x-1)?
The only part you need to fix is that -(ln(5x^2)) should be -(ln(5)+2ln(x))
because in the problem only x is raised to the 2nd power and not the 5. the ln(2x-1) is in simplest form.
So that must be the answer, right? Of course changing 2(ln5+lnx) by ln5+2lnx
exactly (also make sure that end is in parentheses and negated as it's in the denominator)
Ok thank you very much for your help