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anonymous

  • 5 years ago

Guy how do you integrate (3x^2 + 6) ^ 3 Is it.... {(3x^2 + 6)^4} / 4 ??

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  1. anonymous
    • 5 years ago
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    try expanding out the original and then integrating.

  2. anonymous
    • 5 years ago
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    Isnt there an eqn in integration stating (ax + b) ^ n is to be integrated normally like the others?

  3. anonymous
    • 5 years ago
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    nope, if you took the derivative of what you have above you do not get back the function being integrated.

  4. anonymous
    • 5 years ago
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    so the answer that i wrote is wrong?

  5. anonymous
    • 5 years ago
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    yep

  6. anonymous
    • 5 years ago
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    (3x^2 + 6)(3x^2 + 6)(3x^2 + 6) = 27x^6+162x^4+324x^2+216 and integrate

  7. anonymous
    • 5 years ago
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    What if the whole thing is to the power of half?

  8. anonymous
    • 5 years ago
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    what does the problem look like, you may be able to use u-sub?

  9. anonymous
    • 5 years ago
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    ill show you....... (3x^2) / squareroot ( x^2 +4)

  10. anonymous
    • 5 years ago
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    http://integral-table.com/ check this table number 36.

  11. anonymous
    • 5 years ago
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    That last one you gave looks like a candidate for trig sub.

  12. anonymous
    • 5 years ago
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    especially after you factor the 3 out

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spraguer (Moderator)
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