anonymous
  • anonymous
Could anyone please help me with simplifying radicals? -15
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
√(-15) is the problem?
anonymous
  • anonymous
\[\sqrt{-15}\]
anonymous
  • anonymous
what is your question?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
it is odd and cannot be simplfied
anonymous
  • anonymous
ok so if you break it into it's factors you get √(-1)(3)(5) √(-1) = i the rest cannot be simplified so you have i√15 for an answer
anonymous
  • anonymous
√49 is also odd but simplifies to 7 mmolina
anonymous
  • anonymous
so the answer is -1/15
anonymous
  • anonymous
?
anonymous
  • anonymous
no, the answer is: i*srqr(15)
anonymous
  • anonymous
i squared as in india type of i?
anonymous
  • anonymous
\[i*\sqrt{15}\]
anonymous
  • anonymous
hmm never heard of that before. what rule is that derived from?
anonymous
  • anonymous
i is the imaginary unit √(-1) because you cannot take the square root of a negative number.
anonymous
  • anonymous
okay. let me try that...
anonymous
  • anonymous
set in you personal calculator \[\sqrt{-1}\] this will give you an error as the answer. So every time you have an expresion like that you have to write an i in front of the root and make the number inside the root positive.
anonymous
  • anonymous
the entire problem is quadratic formulas which is -1 +/- \[\sqrt{-15}/2\]
anonymous
  • anonymous
then there are no real solutions
anonymous
  • anonymous
I have the left side down and the fraction beneathe, but complicated fixing right side. is that possible for a solution set? the answer must be two separate numbers
anonymous
  • anonymous
not always, quadratics have AT MOST 2 solutions but can have only one or no real solutions, this appears to be a classic no real solutions problem
anonymous
  • anonymous
the solutions to a quadratic are where the graph crossed the x-axis, if you graph the original problem does it cross the x-axis?
anonymous
  • anonymous
there is no graphing, and there is no option for no solution--there is indeed a solution. haha
anonymous
  • anonymous
It might make things simpler if you tell us what the original problem is.
anonymous
  • anonymous
it must form an equation with only addition and subraction signs between them
anonymous
  • anonymous
I did if you look above
anonymous
  • anonymous
:)
anonymous
  • anonymous
hello?
anonymous
  • anonymous
did you not understand it?
anonymous
  • anonymous
I understand that you have simplified the original problem but if you post what the quadratic is then we could verify that your solutions are correct.

Looking for something else?

Not the answer you are looking for? Search for more explanations.