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anonymous
 5 years ago
lim n > infinity (2n+ 2^n) / (3n+3^n)
anonymous
 5 years ago
lim n > infinity (2n+ 2^n) / (3n+3^n)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no cant use that.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not sure if its 2/3 or zero?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i doubt that. i think it should be zero. the first terms are irrelevant since they are linear and the rest is exponential. if we simply erase the first terms you get \[(\frac{2}{3})^n\]which certainly goes to zero. of course this is not a proof.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is 0I used Mathematica to get the answer. I dont know how to get there though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes the wolfram is also showing zero but I dont know how to get there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey should I use??? a(n)  0  < epsilon ???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i still don't know why l'hopital does not apply. take the derivative once, get \[\frac{2+2^nln(2)}{3+3^nln(3)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know we can use it but its analysis course, so I have to find the limit without l'hopital rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do it again, get \[\frac{2^n (ln(2))^2}{3^n (ln(3))^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0any ideas you have....??? but now I m sure its 0. so I m half way I think
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