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anonymous

  • 5 years ago

Karin is playing a game at an after school carnival. There are a number of table tennis balls in a bag, and 1/3 of them are marked as prize-winners. A player randomly selects a ball from the bag, checks to see if they won a prize, and then replaces the ball. If karin plays the game 12 times, what is the probability that she will win a prize exactly 4 times? A.) 0.0004 B.) 0.012 C.) 0.238 D.)0.25

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  1. anonymous
    • 5 years ago
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    anything?

  2. anonymous
    • 5 years ago
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    the probability of winning a prize in one try is 1/3. Since the sample space remains the same for all tries, as the ball is replaced, we caN use binomial distribution in this. The prob. of winning 4 out of 12 is: 12C4 (1/3)^4 (2/3)^8

  3. anonymous
    • 5 years ago
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    is 12C4 suppose to be 12/4?

  4. anonymous
    • 5 years ago
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    its 12!/(4!)(8!)

  5. anonymous
    • 5 years ago
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    so i got 11880/ 24

  6. anonymous
    • 5 years ago
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    which is 495

  7. anonymous
    • 5 years ago
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    so multiply it by the others...

  8. anonymous
    • 5 years ago
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    (1/3)^4 (2/3)^8? so i got 1/81 and 256/6561 now wat...

  9. anonymous
    • 5 years ago
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    multiply the three

  10. anonymous
    • 5 years ago
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    what 3?

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