Karin is playing a game at an after school carnival. There are a number of table tennis balls in a bag, and 1/3 of them are marked as prize-winners. A player randomly selects a ball from the bag, checks to see if they won a prize, and then replaces the ball. If karin plays the game 12 times, what is the probability that she will win a prize exactly 4 times? A.) 0.0004 B.) 0.012 C.) 0.238 D.)0.25

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Karin is playing a game at an after school carnival. There are a number of table tennis balls in a bag, and 1/3 of them are marked as prize-winners. A player randomly selects a ball from the bag, checks to see if they won a prize, and then replaces the ball. If karin plays the game 12 times, what is the probability that she will win a prize exactly 4 times? A.) 0.0004 B.) 0.012 C.) 0.238 D.)0.25

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anything?
the probability of winning a prize in one try is 1/3. Since the sample space remains the same for all tries, as the ball is replaced, we caN use binomial distribution in this. The prob. of winning 4 out of 12 is: 12C4 (1/3)^4 (2/3)^8
is 12C4 suppose to be 12/4?

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Other answers:

its 12!/(4!)(8!)
so i got 11880/ 24
which is 495
so multiply it by the others...
(1/3)^4 (2/3)^8? so i got 1/81 and 256/6561 now wat...
multiply the three
what 3?

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