find the domain of the function: f(x)=to the square root of x2-64

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find the domain of the function: f(x)=to the square root of x2-64

Mathematics
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x2-64 must be equal or greater than zero, that is: x2-4 >=0 if you isolate x, then you end up with: x>=sqrt(4)=2 so the domain is (2, + infinity)
Sorry x2-64 must be equal or greater than zero, that is: x2-64 >=0 if you isolate x, then you end up with: x>=sqrt(64)=8 so the domain is (8, + infinity)
this are the following answers; a.(infinity,8) U (8,infinity) b. (-infinity, infinity), c. (-8,8) d, (-infinity,-8) U [8,infinity)( I don't see ur answer there)

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let me check it out
yeah I was wrong. Remember that sqrt(64) =+8 and -8. So the domain is (-infinity,-8)U(8,+infinity) Sorry
it is d)
yes!

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