anonymous
  • anonymous
construct a truth table for the statement. ∼ (∼p ∧ ∼q)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
method or just answer? usually start with p q t t t f f t f f
anonymous
  • anonymous
so ~p and ~q ~p ~q f f f t t f t t
anonymous
  • anonymous
for (~ p and ~q) they both must be true, so get (~p and ~q) f f f t

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anonymous
  • anonymous
and finally to negate this flip the f and t to get ~(~p and ~q) t t t f
anonymous
  • anonymous
which as you see is the same truth table for p or q. they are the same.
anonymous
  • anonymous
Its a bit easier to read when they are all lined up
anonymous
  • anonymous
IE shows it as a single line of text
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