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anonymous

  • 5 years ago

A debt of $10,000 is to be amortized by equal payments of $400 at the end of each month, plus a final payment after the last $400 payment is made. If the interest is at the rate of 1% compounded monthly (the same as an annual rate of 12% compounded monthly), i. Write a discrete dynamical system that models the situation. ii. Construct a table showing the amortization schedule for the required payments. iii. Find a solution for the system.

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  1. amistre64
    • 5 years ago
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    discrete mathmatics.... thats a higher level college course.

  2. anonymous
    • 5 years ago
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    An=An−1(1.01)−400

  3. amistre64
    • 5 years ago
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    so now balance = past balance(1.01) - 400 ?

  4. anonymous
    • 5 years ago
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    \[A _{n}=A _{n-1}(1.01)-400\]

  5. anonymous
    • 5 years ago
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    yes

  6. amistre64
    • 5 years ago
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    A0 = 10000 the first payment is 10000(1.01) + 400 B[n]=B{n-1}... balance due right?

  7. anonymous
    • 5 years ago
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    yes

  8. anonymous
    • 5 years ago
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    went wrong way should be adding bc of debt

  9. amistre64
    • 5 years ago
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    B{n-1} - B{n-1}(.01) - 400 = B{n} B{n-1}(1-.01) - 400 = B{n} then right?

  10. amistre64
    • 5 years ago
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    how does that look?

  11. amistre64
    • 5 years ago
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    We want the balance or the payments?

  12. anonymous
    • 5 years ago
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    makes sense

  13. anonymous
    • 5 years ago
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    required payments

  14. amistre64
    • 5 years ago
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    the payments are: B{n}(1.01) + 400; right? or you say to negate them to account for debt?

  15. anonymous
    • 5 years ago
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    yes

  16. amistre64
    • 5 years ago
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    -(1.01)B{n} - 400 = B{n+1} then maybe?

  17. anonymous
    • 5 years ago
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    ok how about this For the following affine discrete dynamical systems: a. un=un-1-2 where u0=4 b. un=un-1+3 where u0=1 the value of r is 1, so the solution formulas given in this lesson do not apply. i. Use iteration (by hand or with your calculator) to explore the first few terms of each sequence. ii. On the basis of (i), conjecture a formula for a solution u(n) of the general affine system with r=1: (I) u0=c (R) un=un-1+d for n > 0

  18. anonymous
    • 5 years ago
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    I have the tables

  19. anonymous
    • 5 years ago
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    If I have \[u _{n}=u _{n-1}+d\]

  20. anonymous
    • 5 years ago
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    u0=4

  21. anonymous
    • 5 years ago
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    http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4dcaa12840ec8b0b88f50f17

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