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anonymous

  • 5 years ago

We toss 3 coins 100,000 times. How many times do we expect to see "Exactly 1 Head" appearing? A. 12,500 B. 37,500 C. 3,750 D. 50,000

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  1. anonymous
    • 5 years ago
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    u there?????????????

  2. anonymous
    • 5 years ago
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    Ok, so what do you think?

  3. anonymous
    • 5 years ago
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    I have no idea i dont want to have to make a HUGE table.. >.<

  4. anonymous
    • 5 years ago
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    oh, no I agree.

  5. anonymous
    • 5 years ago
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    But what if we find the probability of just getting 1 head with 3 coins

  6. anonymous
    • 5 years ago
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    i/3rd

  7. anonymous
    • 5 years ago
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    1/3rd sowee bout that ^^

  8. anonymous
    • 5 years ago
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    You sure?

  9. anonymous
    • 5 years ago
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    wait no im not :P

  10. anonymous
    • 5 years ago
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    1/8th?

  11. anonymous
    • 5 years ago
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    3/8 isnt it ? im

  12. anonymous
    • 5 years ago
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    a little lost >.<

  13. anonymous
    • 5 years ago
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    Well, I agree that the total number of outcomes for 3 coins is 8. And if only one is heads it could be the first, the second, or the third coin that lands heads. So I agree 3/8 makes sense

  14. anonymous
    • 5 years ago
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    So what is that as a percentage probability?

  15. anonymous
    • 5 years ago
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    isnt that 37.5%?

  16. anonymous
    • 5 years ago
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    So then it would be B wouldnt it? :D

  17. anonymous
    • 5 years ago
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    Yes. So doesn't that mean in 100 throws of 3 coins we should have 37.5 times just having 1 head. So in 100 thousand it should be 37.5 thousand. Yes, the answer is B

  18. anonymous
    • 5 years ago
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    because 100,000 / 8 * 3 = 37500

  19. anonymous
    • 5 years ago
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    correct?

  20. anonymous
    • 5 years ago
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    That is another way to think about it yes =)

  21. anonymous
    • 5 years ago
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    Alrighty :) Thanks!

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