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anonymous
 5 years ago
find dy/dx at x=0
y=u(2/u)
u= (3x+1)^3
anonymous
 5 years ago
find dy/dx at x=0 y=u(2/u) u= (3x+1)^3

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1dy/du = 1+(2/u^2) du/dx = 3*3(3x+1)^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.12 9(3x+1)^2 (1+  ) * ( ) (3x+1)^6 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.118(3x+1)^2 9(3x+1)^2 +  (3x+1)^6 9(3x+1)^6 + 18  ?? (3x+1)^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get dy/du =u(2/u)?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1y = u (2/u) dy = 1  (2/u^2) du dy/du = 1 + (2/u^2)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1at x=0; id say that i did the calculation right and go with: 27

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you could simply plug the value of u into the equation for f(u)... but the chain rule makes life easier
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