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anonymous

  • 5 years ago

Solution to figure out a quadratic equation: 3, -2. Show work.

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  1. anonymous
    • 5 years ago
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    if the solutions are 3 and -2, it means that the quadratic was like this: (x-3)(x+2)=0 expand that.

  2. anonymous
    • 5 years ago
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    If those are the roots then the factors are: (x-3)(x+2) Expand the brakcets \[y=x ^{2}-x-6\]

  3. anonymous
    • 5 years ago
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    cocnutshake, your equation is right, but y HAS to be equal to 0.

  4. anonymous
    • 5 years ago
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    So once you have y=x^2-x-6, how do you get Y to =0

  5. anonymous
    • 5 years ago
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    no no, use my equation.

  6. anonymous
    • 5 years ago
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    that's what i meant oops..

  7. anonymous
    • 5 years ago
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    okay

  8. anonymous
    • 5 years ago
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    if the solution to the quadratic is 3, -2 it means that the quadratic was (x-3)(x+2)=0, only then, if you substitute x = 3 or x =-2 you will get LHS = RHS, which means only for this particular quadratic, 3,-2 are the solutions.

  9. anonymous
    • 5 years ago
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    thank you

  10. anonymous
    • 5 years ago
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    np

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