I have eoct tomorrow. i don't get the quadratic formula. the question is, "solve the equation using the quadratic formula" x2 + 3x - 7 = 0 What's a,b, and c?

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I have eoct tomorrow. i don't get the quadratic formula. the question is, "solve the equation using the quadratic formula" x2 + 3x - 7 = 0 What's a,b, and c?

Mathematics
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The quadratic formula is: \[ax^2 + bx + c = 0 \implies x = \frac{-(b) \pm \sqrt{(b)^2 - 4(a)(c)}}{2(a)}\]
So looking at your equation: \[x^2 + 3x - 7 = 0\] What number corresponds to a, b, and c?
x^2=a 3x=b 7=c?

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Ok, so If I plug in those values for a, b, and c in the left part of my formula I should get the equation you have.
\[(x^2)x^2 + (3x)x + (7) = 0\] Is that your equation?
Still thinking?
no theres only 1 x^2 x2 + 3x - 7 = 0 thats my equation
right. So what do we need to put in the blanks: \[( )x^2 + ()x + () = 0\] To get something that is equal to your equation?
Err equivalent rather.

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