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anonymous
 5 years ago
Find the second derivative of x^2y^2=1
anonymous
 5 years ago
Find the second derivative of x^2y^2=1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Have you covered implicit differentiation? If so, here goes: d/dx(x^2 +y^2 = 1) = 2x + 2ydy/dx = 0, so dy/dx = x/y. Differentiating dy/dx gives (using the quotient rule) gives d^2y/dx^2 = ( y +xdy/dx)/y^2 Substituting for dy/dx gives the second differential (x^2 + y^2)/y^3
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