A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Find the area of a triangle whose sides measure 13 feet, 13 feet, and 10 feet.
anonymous
 5 years ago
Find the area of a triangle whose sides measure 13 feet, 13 feet, and 10 feet.

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here is the hint:Copy the diagram on your own paper, and connect the centers of two large circles and the center of the small circle to form a 45° 45° 90° triangle. Each radius of the larger circles will be s/4. Use the properties of special right triangles and algebra to find the radius of the smaller circle.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is the formula= Base x Hieght divided by 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what number that i use?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Triangle is isosceles. Draw triangle drop perpendicular from vertex opposite side of 10 feet. It meets the 10 feet side at right angles and bisects the side. You now have two triangles with sides 13, 5 and 12. 12 is the height. Area = !/2(base of 10)(height of 12) = 60 sqft
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.