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anonymous

  • 5 years ago

Find the area of a triangle whose sides measure 13 feet, 13 feet, and 10 feet.

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  1. anonymous
    • 5 years ago
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    here is the hint:Copy the diagram on your own paper, and connect the centers of two large circles and the center of the small circle to form a 45°- 45°- 90° triangle. Each radius of the larger circles will be s/4. Use the properties of special right triangles and algebra to find the radius of the smaller circle.

  2. anonymous
    • 5 years ago
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    Here is the formula= Base x Hieght divided by 2

  3. anonymous
    • 5 years ago
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    so what number that i use?

  4. anonymous
    • 5 years ago
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    Triangle is isosceles. Draw triangle drop perpendicular from vertex opposite side of 10 feet. It meets the 10 feet side at right angles and bisects the side. You now have two triangles with sides 13, 5 and 12. 12 is the height. Area = !/2(base of 10)(height of 12) = 60 sqft

  5. anonymous
    • 5 years ago
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    oh okay thank

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