Find the area of a triangle whose sides measure 13 feet, 13 feet, and 10 feet.

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Find the area of a triangle whose sides measure 13 feet, 13 feet, and 10 feet.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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here is the hint:Copy the diagram on your own paper, and connect the centers of two large circles and the center of the small circle to form a 45°- 45°- 90° triangle. Each radius of the larger circles will be s/4. Use the properties of special right triangles and algebra to find the radius of the smaller circle.
Here is the formula= Base x Hieght divided by 2
so what number that i use?

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Triangle is isosceles. Draw triangle drop perpendicular from vertex opposite side of 10 feet. It meets the 10 feet side at right angles and bisects the side. You now have two triangles with sides 13, 5 and 12. 12 is the height. Area = !/2(base of 10)(height of 12) = 60 sqft
oh okay thank

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