Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Joe has a collection of nickels and dimes that is worth $6.10. If the number of dimes was tripled and the number of nickels was decreased by 49, the value of the coins would be $14.05. How many nickels and dimes does he have?
 2 years ago
 2 years ago
Joe has a collection of nickels and dimes that is worth $6.10. If the number of dimes was tripled and the number of nickels was decreased by 49, the value of the coins would be $14.05. How many nickels and dimes does he have?
 2 years ago
 2 years ago

This Question is Closed

3pwoodBest ResponseYou've already chosen the best response.0
Let: n = number of nickles d = number of dimes we know from the problem statement that: 0.05n + 0.1d = 6.10 and 0.05(n49) + 0.1*(3d) = 14.05 To solve, we have to solve one equation for one variable (doesn't matter which): 0.05n + 0.1d = 6.10 n = (6.10  0.1d)/0.05 n = 122  2d then substitute that into the other equation and solve: 0.05(n49) + 0.1*(3d) = 14.05 0.05([1222d]49) + 0.1*(3d) = 14.05 6.10  0.1d  2.45 + 0.3d = 14.05 .2d = 10.4 d = 52 then plug that into any of the previous equations to find n: n = 122  2d n = 122  2(52) n = 18
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.