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anonymous
 5 years ago
Let the function f(x) be defined by the equation y = f(x), where x and f(x) are real numbers.
f(x) = 4 − x^2
f(9) =
f(7) =
f(k) =
f(k2 − 8) =
anonymous
 5 years ago
Let the function f(x) be defined by the equation y = f(x), where x and f(x) are real numbers. f(x) = 4 − x^2 f(9) = f(7) = f(k) = f(k2 − 8) =

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(9)=77 f(7)=45 f(k)=4k^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm not sure about the last one, sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no worries.. how did you get 77? I want to try and understand this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just put in 9 to the equation so f(9)=49^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Last one is 2k8? or k^28?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got it.. i was trying to multiply it instead of subtracting it...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0andras 2k8 nor k^28 are correct for the final answer ive tried them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm, but my question was what is k2 here: f(k2 − 8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ f(k^2 − 8) = \] is the equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u just have to put k^28 into the function. So it will be f(k^28)= 4(k^28)^2=k^2+16k60

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and I guess k is just a free parameter here
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