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anonymous

  • 5 years ago

Let the function f(x) be defined by the equation y = f(x), where x and f(x) are real numbers. f(x) = 4 − x^2 f(9) = f(-7) = f(k) = f(k2 − 8) =

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  1. anonymous
    • 5 years ago
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    f(9)=-77 f(-7)=-45 f(k)=4-k^2

  2. anonymous
    • 5 years ago
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    i'm not sure about the last one, sorry

  3. anonymous
    • 5 years ago
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    no worries.. how did you get -77? I want to try and understand this

  4. anonymous
    • 5 years ago
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    Just put in 9 to the equation so f(9)=4-9^2

  5. anonymous
    • 5 years ago
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    Last one is 2k-8? or k^2-8?

  6. anonymous
    • 5 years ago
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    i got it.. i was trying to multiply it instead of subtracting it...

  7. anonymous
    • 5 years ago
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    :)

  8. anonymous
    • 5 years ago
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    andras 2k-8 nor k^2-8 are correct for the final answer ive tried them

  9. anonymous
    • 5 years ago
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    hmm, but my question was what is k2 here: f(k2 − 8)

  10. anonymous
    • 5 years ago
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    \[ f(k^2 − 8) = \] is the equation

  11. anonymous
    • 5 years ago
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    u just have to put k^2-8 into the function. So it will be f(k^2-8)= 4-(k^2-8)^2=-k^2+16k-60

  12. anonymous
    • 5 years ago
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    and I guess k is just a free parameter here

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