anonymous
  • anonymous
A business purchases a computer system for $3000. If the value of the system decreases at a rate of 15% per year, how much is the computer worth after 4 years?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
you multiply by .85 repeatedly, so 3000*.85^4 .85 because 100% = 1.00 and 15% decrease = 1.00 - .15 = .85
anonymous
  • anonymous
Wait huh? :I
anonymous
  • anonymous
what part is confusing, I'll try to make it make sense...

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anonymous
  • anonymous
3000 * .85 = 2550 (after one year) 2550 * .85 = 2167.5 (after two years) but look, 2550 = 3000*.85, so after the second year can be found by: (3000*.85)*.85 which equals 3000*.85^2 so after 4 years, the exponent becomes a 4
anonymous
  • anonymous
Each year its value decrease by 15% of its original value. In 4 years, it will decrease by 4*15%=60%. That means it will cost just 40% of its original value. So, its value after 4 years is: (40/100)*3000=$1,200
anonymous
  • anonymous
No, the answer is not 1200
anonymous
  • anonymous
because it is not losing 15% of 3000 each year. the second year, you lose 15% of a smaller number.
anonymous
  • anonymous
OMG, Stick with tonks :)
anonymous
  • anonymous
By AnwarA's calculation, you would have no money after 8 years, but you can lose 15% for ever
anonymous
  • anonymous
Aha, I'm still trying to figure the problem out myself
anonymous
  • anonymous
Monie, does using .85 make sense?
anonymous
  • anonymous
Yea it does
anonymous
  • anonymous
okay, then do it out slowly instead of any shortcuts
anonymous
  • anonymous
But why .85?
anonymous
  • anonymous
oh, if there were no change, you would have 100% the next year. Since there is a 15% decrease, you have 15% less than 100%, or 85% next year. Then move the decimal over to turn a percent into something you can multiply with for .85
anonymous
  • anonymous
I end up with 0.7225...Is that correct? .-.
anonymous
  • anonymous
hmmm, 3000*.85 = year 1 (3000*.85)*.85 = year 2 ((3000*.85)*.85)*.85 = year 3 (((3000*.85)*.85)*.85)*.85 = year 4 = 3000*.85*.85*.85*.85 = ...
anonymous
  • anonymous
do you see why each step works? What do you get?
anonymous
  • anonymous
I get 1556.01875.... But I'm guessing it to be 1556? Correct?
anonymous
  • anonymous
I think you should keep it to the penny, 1556.02
anonymous
  • anonymous
yes, do you get the .85 and the repeated multiplying?
anonymous
  • anonymous
Yes I do :). THank you so very much for helping me Tonks.
anonymous
  • anonymous
ur welcome
anonymous
  • anonymous
One more question if you don't mind? (:
anonymous
  • anonymous
If it is a math problem, post it as a new thread

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