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anonymous
 5 years ago
can someone help w/ logs
anonymous
 5 years ago
can someone help w/ logs

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what would you like to know? the main thing to remember is that logs are actually exponents (until you get to fancy math) so all the laws of exponents apply.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait thats wrong what i posted

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0has nothing to do with logs.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops i lied excuse me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes it does you have to multiply each side by a log...huh?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no you do not 'multiply' by the log you 'take the log'

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can choose any base you like, but I will use \[log_e\] which is written \[ln\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i mean...im so confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take the log of both sides to get \[ln(3^{x+1})=ln(6^x)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then what? log and what base? dont u mean log3 (log base 3 i mean)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then the exponents come out as multipliers to give \[(x+1)ln(3)=xln(6)\] we solve this equation for x, remembering that \[ln(3)\] and \[ln(6)\] are just constants.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you "take" ln and use a ln properties... (x+1)ln3=xln6 (x+1)/x = ln6/ln3 1+ 1/x=ln6/ln3 1/x=ln6/ln3 1 x=ln3/(ln6ln3) you can use log with base of 3 as well...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me start slowly. You have two different bases here, 3 and 6. whatever you do to one side you must do the same to the other. you cannot take the log base 3 of one side and the log base 6 of the other.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok what do i do after (x+1) log (3) = x log 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0both sides... 6=3*2, so you can present log3 (3*2)= 1+log3(2) (log3  log with base of 3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahhh too many people are helping me im so confused

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the same as in ln... you'll have ln or log in answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me see if i can unconfuse you. how do you solve any equation with the variable in the exponent? for example how would you solve \[2^x=1000\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you cannot use 'algebra' because the variable is in the sky. it is in the exponent not on the ground floor, so you cannot add or subtract, multiply or divide to solve for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you solve it by taking the log of both sides, because one of the facts of logs is that \[log_b(a^x)=xlog_b(a)\] and now the variable is on the ground floor. so can solve using algebra

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if i want to solve \[2^x=1000\] for x i take the log of both sides and get \[log(2^x)=log(1000\] \[xlog(2)=log(1000)\] \[x=\frac{log(1000)}{log(2)}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now you have \[3^{x+1}=6^x\] tale the log of both sides to get \[log(3^{x+1})=log(6^x)\] \[(x+1)log(3)=xlog(6)\] multiply out to get \[x\log(3)+log(3)=xlog(6)\] \[log(3)=xlog(6)xlog(3)\] \[log(3)=x(log(6)log(3))\] \[\frac{log(3)}{log(6)log(3)}=x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which base is the log? it doesn't matter. but if you want a number out of this you have to use a base that you can find on your calculator. you can use log base ten which is just written as log or you can use log base e which is written as ln.
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