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ttsmith7394
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hey, im in 9th and need help with algebra; trinomials. if you cold help me that would be great. thanks,
 3 years ago
 3 years ago
ttsmith7394 Group Title
hey, im in 9th and need help with algebra; trinomials. if you cold help me that would be great. thanks,
 3 years ago
 3 years ago

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3pwood Group TitleBest ResponseYou've already chosen the best response.0
What do you need help with, specifically?
 3 years ago

ttsmith7394 Group TitleBest ResponseYou've already chosen the best response.0
r(square) + 2r = 24
 3 years ago

3pwood Group TitleBest ResponseYou've already chosen the best response.0
Solving for r? There are so many ways of doing this it's not even funny. Here are a few: Quadratic equation: http://en.wikipedia.org/wiki/Quadratic_equation r^2 + 2r  24 = 0 so r = [2 ± sqrt(2^2  4*1*(24))] / [2*1] r = 4 or 6 Completing the square: r^2 + 2r = 24 r^2 + 2r + (2/2)^2 = 24 + (2/2)^2 r^2 + 2r + 1 = 25 (r + 1) ^ 2 = 25 r + 1 = ±sqrt(25) r + 1 = ±5 r = 1 ±5 r = 4 or 6 SeatofthePants Factoring: r^2 + 2r  24 = 0 (try to find two numbers that sum to 2 and multiply to 24) 1 * 24 = 24 but they don't sum to 2 3 * 8 =  24 but they dont' sum to 2 4 * 6 =  24 and they do sum to 2. That's the set we need. so this expression can be factored like so: (r^2 + 2r  24 = (r  4)(r+6) And this new expression will only equal zero if one of the terms in parentheses equals zero. That'll only happen at r = 4 or 6
 3 years ago
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