anonymous
  • anonymous
Write quadratic equation in standard form with given solution set: {1/6, -2/3}
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
since 1/6 is a zero on factor is \[x-\frac{1}{6}\] another is \[x+\frac{2}{3}\] so you could write \[(x-\frac{1}{6})(x+\frac{2}{3})\]
anonymous
  • anonymous
but instead you would probably write \[(6x-1)(3x+2)\] standard form means multiply this out to get \[18x^2+9x-2\] if my algebra is correct.
anonymous
  • anonymous
And then what? Use the quadratic formula?

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anonymous
  • anonymous
no. you already have the zeros. you were given that the zeros are \[\frac{1}{6}\] and \[-\frac{2}{3}\] so you are not being asked to find the zeros. this question is asked in reverse. not "here is the equation, find the zeros" but rather "here are the zeros, find the equation"
anonymous
  • anonymous
So the equation would be my final answer then, right?
anonymous
  • anonymous
if you are given that the zeros are a and b then the equation must have been \[(x-a)(x-b)=0\]
anonymous
  • anonymous
yes the equation is what you were asked for. if i multiplied out correctly, your answer should be \[18x^2+9x-2=0\]
anonymous
  • anonymous
Awesome, thank you so much.
anonymous
  • anonymous
welcome, but check my algebra, i am tired.
anonymous
  • anonymous
It is correct.

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