anonymous
  • anonymous
-6x^2 + 48 = 0
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
subtract 48 from both sides: -6x^2=-48 divide both sides by (-6): x^2=8 take square root both sides: x=sq.rt(2*4)=2sq.rt(2)
anonymous
  • anonymous
add 6x^2 to both sides, divide by 6, that the square root. don't forget the plus or minus
anonymous
  • anonymous
inik i dont think your answer is in a format my teacher is looking for. Right now im doing test corrections and my teacher marked me down for putting the answer as " +- 8"

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[-6x^2=-48\] \[6x^2=48\] \[x^2=\frac{48}{6}=8\] \[x=\sqrt{8}\] or \[x=-\sqrt{8}\] and since \[\sqrt{8}=\sqrt{4\times 2}=\sqrt{4}\times \sqrt{2}= 2\sqrt{2}\] your teacher might prefer the answer written in 'simplest radical form'

Looking for something else?

Not the answer you are looking for? Search for more explanations.