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anonymous

  • 5 years ago

Need help w/ linear differential equations... If: L1=D+1, L2=D-2X^2 ; where D is your differential operator. What is L1L2 and L2L1?

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  1. anonymous
    • 5 years ago
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    what is L1 & L2...?

  2. anonymous
    • 5 years ago
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    function,operator...?

  3. anonymous
    • 5 years ago
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    Its in the question, D is the differential operator.

  4. anonymous
    • 5 years ago
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    if I'm reading it correctly...: L1L2=(D+1)*(D-2x^2)=D^2 -D(2x^2) +D(1) - 2x^2=D^2 -4x -2x^2

  5. anonymous
    • 5 years ago
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    The answer for L1L2 is: D^2+(D-2x)D-2x(x+2)

  6. anonymous
    • 5 years ago
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    I just don't understand how they got that..

  7. anonymous
    • 5 years ago
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    me too... looking at that now... may be light will come up..:) give me a min

  8. anonymous
    • 5 years ago
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    o.k thanks.

  9. anonymous
    • 5 years ago
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    what they are asking is to show that L1L2 does not equal L2L1.

  10. anonymous
    • 5 years ago
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    can't get it... I see D^2 + (D-2x)D... but where is -2x(x+2) comes from?

  11. anonymous
    • 5 years ago
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    yeah, thats what I thought...

  12. anonymous
    • 5 years ago
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    I dont know if they are doing some product rule....

  13. anonymous
    • 5 years ago
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    L2L1 is D^2+(1-2X)D-2x^2

  14. anonymous
    • 5 years ago
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    I'll play with it... let you know

  15. anonymous
    • 5 years ago
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    thanks.

  16. anonymous
    • 5 years ago
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    still getting L1L2=L2L1... did you try internet?

  17. anonymous
    • 5 years ago
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    yeah. I dont think that they are just multiplying them together

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