anonymous
  • anonymous
Solve using quadratic formula: 10x^2+10x=-3 I got my answer as -10+/- i(sq.root) 5 --------- 10 is that right?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[10x^2+10x+3=0\] \[a=10,b=10,c=3\] ok i think you forgot to divide -10 also. it should be \[\frac{-5+\sqrt{5}i}{10}\]
anonymous
  • anonymous
i will write it out if you like
anonymous
  • anonymous
Okay yeah that might help.

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anonymous
  • anonymous
\[x=\frac{-10+\sqrt{10^2-4\times 10 \times 3}}{2\times 10}\] \[=\frac{-10+\sqrt{100-120}}{20}\] \[=\frac{-10+\sqrt{-20}}{20}\]
anonymous
  • anonymous
so far so good. \[=\frac{-10+\sqrt{4\times 5\times -1}}{20}\] \[=\frac{-10+2\sqrt{5}i}{20}\] \[=\frac{2(-5+\sqrt{5}i}{20})\] \[=\frac{-5+\sqrt{5}i}{10}\] think this is right.
anonymous
  • anonymous
of course you should have the 'plus or minus"

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