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anonymous

  • 5 years ago

x^-1 + y^-1 ----------- 3x^-2 +5y^-2 please show me the steps and final answer, thanks.

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  1. anonymous
    • 5 years ago
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    Step 1 top line: add the two fractions 1/x and 1/y (you should get (x+y)/xy Step 2 bottom line: add the two fractions 3/x^2 and 5/y^2 to get (5x^2 + 3y^2)/x^2y^2 You should be OK from here

  2. anonymous
    • 5 years ago
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    Remember when dividing by a fraction to turn it upside down and multiply, then cancel what you can and you're done

  3. anonymous
    • 5 years ago
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    So I'm getting my final answer to be: x+y --- 8

  4. anonymous
    • 5 years ago
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    Pretty sure thats wrong though...

  5. anonymous
    • 5 years ago
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    mmmm...I get Step1 divided by Step 2 (x+y)/xy divided by (5x^2 + 3y^2)/x^2y^2 which is (inverting the bottom fraction) (x+y)/xy multiplied by x^2y^2/(5x^2 + 3y^2) cancel the xy top and bottom to get xy(x+y)/(5x^2 + 3y^2) let me know if you agree

  6. anonymous
    • 5 years ago
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    So you're getting X+Y --- 5X^2+3Y^2 ?

  7. anonymous
    • 5 years ago
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    No, top line is xy(x+y). Bottom line is OK

  8. anonymous
    • 5 years ago
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    Wouldn't that factor out on the top then?

  9. anonymous
    • 5 years ago
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    Not quite sure what you mean by 'factor out', but no, there's nothing more you can cancel or do. You could multiply out the top line as \[x^2y + xy^2\] if you want, but I assume you are to factor out fully so my answer is still \[xy(x+y)/(5x^2+3y^2)\]

  10. anonymous
    • 5 years ago
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    Alright, thank you.

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