x^-1 + y^-1 ----------- 3x^-2 +5y^-2 please show me the steps and final answer, thanks.

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x^-1 + y^-1 ----------- 3x^-2 +5y^-2 please show me the steps and final answer, thanks.

Mathematics
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Step 1 top line: add the two fractions 1/x and 1/y (you should get (x+y)/xy Step 2 bottom line: add the two fractions 3/x^2 and 5/y^2 to get (5x^2 + 3y^2)/x^2y^2 You should be OK from here
Remember when dividing by a fraction to turn it upside down and multiply, then cancel what you can and you're done
So I'm getting my final answer to be: x+y --- 8

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Pretty sure thats wrong though...
mmmm...I get Step1 divided by Step 2 (x+y)/xy divided by (5x^2 + 3y^2)/x^2y^2 which is (inverting the bottom fraction) (x+y)/xy multiplied by x^2y^2/(5x^2 + 3y^2) cancel the xy top and bottom to get xy(x+y)/(5x^2 + 3y^2) let me know if you agree
So you're getting X+Y --- 5X^2+3Y^2 ?
No, top line is xy(x+y). Bottom line is OK
Wouldn't that factor out on the top then?
Not quite sure what you mean by 'factor out', but no, there's nothing more you can cancel or do. You could multiply out the top line as \[x^2y + xy^2\] if you want, but I assume you are to factor out fully so my answer is still \[xy(x+y)/(5x^2+3y^2)\]
Alright, thank you.

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