anonymous
  • anonymous
x^-1 + y^-1 ----------- 3x^-2 +5y^-2 please show me the steps and final answer, thanks.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Step 1 top line: add the two fractions 1/x and 1/y (you should get (x+y)/xy Step 2 bottom line: add the two fractions 3/x^2 and 5/y^2 to get (5x^2 + 3y^2)/x^2y^2 You should be OK from here
anonymous
  • anonymous
Remember when dividing by a fraction to turn it upside down and multiply, then cancel what you can and you're done
anonymous
  • anonymous
So I'm getting my final answer to be: x+y --- 8

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anonymous
  • anonymous
Pretty sure thats wrong though...
anonymous
  • anonymous
mmmm...I get Step1 divided by Step 2 (x+y)/xy divided by (5x^2 + 3y^2)/x^2y^2 which is (inverting the bottom fraction) (x+y)/xy multiplied by x^2y^2/(5x^2 + 3y^2) cancel the xy top and bottom to get xy(x+y)/(5x^2 + 3y^2) let me know if you agree
anonymous
  • anonymous
So you're getting X+Y --- 5X^2+3Y^2 ?
anonymous
  • anonymous
No, top line is xy(x+y). Bottom line is OK
anonymous
  • anonymous
Wouldn't that factor out on the top then?
anonymous
  • anonymous
Not quite sure what you mean by 'factor out', but no, there's nothing more you can cancel or do. You could multiply out the top line as \[x^2y + xy^2\] if you want, but I assume you are to factor out fully so my answer is still \[xy(x+y)/(5x^2+3y^2)\]
anonymous
  • anonymous
Alright, thank you.

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