Divide and express remainder as a fraction: (3x^2+4x-10) -div. by- (x+2)

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Divide and express remainder as a fraction: (3x^2+4x-10) -div. by- (x+2)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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(3x^2+4x-10)/(x+2)=3x-2 with remainder -6/(x+2)
Can you show how you got that?
In the (x+2) part x goes into (3x^2) 3x times. Multiply 3x times x and you get 3x^2 and multiply 3x times 2 and you get 6x. Now subtract (3x^2+6x) from (3x^2+4x) and you get -2x and bring the -10 down. Now x in the x+2 goes into (-2x) -2 times. Multiply -2 times x and you get -2x and multiply -2 times +2 and you get -4. Again you do a subtraction. Subtract (-2x-4) from (-2x-10) and you get a remainder of -6. As a fraction -6 is shown as -6/(x+2).

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