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anonymous

  • 5 years ago

Divide and express remainder as a fraction: (3x^2+4x-10) -div. by- (x+2)

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  1. gw2011
    • 5 years ago
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    (3x^2+4x-10)/(x+2)=3x-2 with remainder -6/(x+2)

  2. anonymous
    • 5 years ago
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    Can you show how you got that?

  3. gw2011
    • 5 years ago
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    In the (x+2) part x goes into (3x^2) 3x times. Multiply 3x times x and you get 3x^2 and multiply 3x times 2 and you get 6x. Now subtract (3x^2+6x) from (3x^2+4x) and you get -2x and bring the -10 down. Now x in the x+2 goes into (-2x) -2 times. Multiply -2 times x and you get -2x and multiply -2 times +2 and you get -4. Again you do a subtraction. Subtract (-2x-4) from (-2x-10) and you get a remainder of -6. As a fraction -6 is shown as -6/(x+2).

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