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anonymous

  • 5 years ago

I would greatly appreciate any help! Thanks so much (2x(1/3))/1-(1/3)^2

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  1. anonymous
    • 5 years ago
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    confused a bit. looks like \[\frac{2x \times \frac{1}{3}}{1-(\frac{1}{3})^2}\] but that doesn't really make sense.

  2. anonymous
    • 5 years ago
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    perhaps the 'x' is a times sign?

  3. anonymous
    • 5 years ago
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    lol oh yes, I'm sorry. The x was a multiplication sign.

  4. anonymous
    • 5 years ago
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    ah so it is \[\frac{2\times \frac{1}{3}}{1-(\frac{1}{3})^2}\]

  5. anonymous
    • 5 years ago
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    we get \[\frac {\frac{2}{3}}{1-\frac{1}{9}}\]

  6. anonymous
    • 5 years ago
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    Yes, exactly! And I'm stuck. I got my answer as (18/27)/9 which I highly doubt is correct.

  7. anonymous
    • 5 years ago
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    \[=\frac{\frac{2}{3}}{\frac{8}{9}}\] \[=\frac{2}{3}\times \frac{9}{8}\] \[=\frac{3}{4}\] if my arithmetic is correct.

  8. anonymous
    • 5 years ago
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    How may I ask did you get 8/9?

  9. anonymous
    • 5 years ago
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    \[1-\frac{1}{9}=\frac{9}{9}-\frac{1}{9}=\frac{8}{9}\]

  10. anonymous
    • 5 years ago
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    lol aye yi yi, thank you so much. I really appreciate it.

  11. anonymous
    • 5 years ago
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    welcome!

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spraguer (Moderator)
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