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anonymous
 5 years ago
use algebraic methods to determine the domain and range for the function from to defined by the given equation.
a. x^2 – 6x –y =0
b. 4x^2 – xy +1 = 0
c. 5x^2(y) – x + 2 = 0
anonymous
 5 years ago
use algebraic methods to determine the domain and range for the function from to defined by the given equation. a. x^2 – 6x –y =0 b. 4x^2 – xy +1 = 0 c. 5x^2(y) – x + 2 = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use algebraic methods to determine the domain and range for the function from x to y defined by the given equation. a. x^2 – 6x –y =0 b. 4x^2 – xy +1 = 0 c. 5x^2(y) – x + 2 = 0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1(a) x^26xy=0 we can solve this for x by using the quadratic formula \[x=\frac{6 \pm \sqrt{364(y)}}{2}=\frac{6 \pm \sqrt{36+4y}}{2}\]

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1what does y have to be in order for x to exist?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am not sure? this question is confusing

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1can you have a negative under the square root?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you want 36+4y to be bigger than or equal to zero, correct?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so solve this for y: 36+4y>=0 and you will have your range

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do i write the range

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1to find range we solve for x to find domain we solve for y so solve the orignal equation for y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so y >= 9 is the range or domain?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think you are supposed to solve each of these for y and think of y as a function of x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but there is something wrong here because you have these each set = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that is what my project say

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1y is range we got y>=9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok fine. so first one is \[x^26xy=0\] so \[y=x^26x\] as a function \[f(x)=x^26x\] domain all real numbers since it is a polynomial range is 9 to infinity

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1no we find domain solve x^26xy=0 for x and you will see the domain is all real numbers because x^26x is a polynomial

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0LOL u guys are great help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0second one. \[4x^2xy+1=0\] \[xy=4x^2+1\] \[y=\frac{4x^2+1}{x}\] domain all real numbers except 0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1all you have to do is solve both for x and y when you solve for x you can find the range when you solve for y you can find the domain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the second one does not have a range

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0range is also all real numbers except 0 because the numerator is \[4x^2+1\] which cannot be 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, range is just the possible y values. y can be anything except 0 since the numerator of your fraction is never 0

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1range is [4,4] you find once you solve for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops really? i will try it.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1oops o did somehting wrong its (inf,4]U[4,inf)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this for the second problem

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1the problem that we are now we are finding range

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how do you like that. you get \[y^216\]under the radical so \[y^216\geq 0\] who knew?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you remember all that inverse crap right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh of course. this thing is a rational function with a slant asymptote. so it does skip values, never between 4 and 4. must be late!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the range is (inf, 4)U(4,inf)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is the last one \[5x^2yx+2=0\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes you have the range correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i have the last one correct is is \[y=\frac{x2}{5x^2}\] domain all numbers except 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0honestly i am little confused by this. myininaya said solve for x. i can try it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i use the quadratic formula i see under the radical \[120y\] meaning \[120y\geq 0\] \[y\leq \frac{1}{20}\] would held if i had the picture of this thing to see if that makes sense.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so i think i will stick to that answer, and go to bed.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you want me to check your range? lol which one is this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0last one. i have confused myself.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1if i didnt make a mistake here is the range

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i must be tired if i cannot multiply 4 by 5 by 2! i best retire.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1yeah you were close then we also have y in the denominator and we know we cannot divide by 0 and when y is 0 the denominator is 0 so our range does not include y=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok maybe but i am still skeptical. what do you get if x = 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0looks like if x = 2, then y = 0 original equation is \[5x^2yx+2=0\] replace x by 2 get \[20y2+2=0\] \[20y=0\] \[y=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i should switch back to windows and run maple, graph the thing and then i would be more convinced.

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1well and also the quadratic formula just failes when a=0 in this case when 5yx^2=0 since y=0 a=0 so the quadratic formula won't work for that part of the answer

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so the range is (inf,1/40]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am afraid i do not believe that either.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0as x goes to infinity \[\frac{x2}{5x^2}\] goes to zero

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1right there is a horizontal asymptote

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0bet you get something closer to 0 than 1/40

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh wait. maybe it is always negative. oops. ok possible

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i am beginning to believe it. may be always less than 1/40. tomorrow i graph !

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1hey satelittle you know what would really convince you? i do

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1you know how to find the maximum right? that derivative crap?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1f'(x)=[5x^210x(x2)]/[(5x^2)]^2=[5x^2+20x]/(25x^4) a critical numbers isfour f(4)=1/40

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well it is nice and late and i have had a few beers. but it looks like extreme value at 0 and 4

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1well 0 doesn't exist in the orignal function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.00 is out, 4 gives.... holy carp, what do you know.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0learn something new every day. thanks.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0me. use it all the time when i am not running linux

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1well it is a nice friend to have

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and so to bed, before i make more of a fool of myself. take care
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